Topic: Magnetic Effects of Current
Subtopic: Magnetic Field Due to Straight Current Carrying Wire
A point charge q is in motion with velocity \[\overrightarrow{v}] relative to an inertial axis 'A'. The instantaneous location of q with respect to a fixed observation point P is \[\overrightarrow{r}\] as shown. \[\overrightarrow{B}\]
the magnetic field at point P is given by :
\[\overrightarrow{B}=\frac{\mu_{0}q}{4\pi}\frac{(\overrightarrow{r}\times \overrightarrow{v})}{r^{3}}\]
\[\overrightarrow{B}=\frac{\mu_{0}q}{2\pi}\frac{(\overrightarrow{v}\times \overrightarrow{r})}{r^{3}}\]
\[\overrightarrow{B}=\frac{\mu_{0}q}{4\pi}\frac{(\overrightarrow{v}\times \overrightarrow{r})}{r^{3}}\]
No solution provided for this question.
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