Rankers Physics

Uncategorized: Practice Problem & Solution

In the circuit, shown in fig. ‘K’ is open. The charge on capacitor C in steady state is q1. Now key is closed and at steady state, the charge on C is q2. The ratio of charges \[\left( \frac{q_{1}}{q_{2}} \right)\] is Physics diagram: In the circuit, shown in fig. ‘K’ is
3/2
2/3
1
1/2

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