
Solution:
Both the parts can be taken as separate capacitors connected in parallel.
So, C=C1+ C2=\(\frac{\varepsilon_{0A}}{d}\frac{\left( K_{1} +K_{2}\right)}{2}\)
Both the parts can be taken as separate capacitors connected in parallel.
So, C=C1+ C2=\(\frac{\varepsilon_{0A}}{d}\frac{\left( K_{1} +K_{2}\right)}{2}\)
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