Solution:

Let's break this down step by step.

1. Resistances connected in parallel

When $n$ resistors, each of resistance $r$, are connected in parallel, the total or equivalent resistance $R_{\text{parallel}}$ is given by the formula:

$$\frac{1}{R_{\text{parallel}}} = \frac{1}{r} + \frac{1}{r} + \cdots + \frac{1}{r} \quad \text{(n terms)}$$

This simplifies to:

$$\frac{1}{R_{\text{parallel}}} = \frac{n}{r}$$

So, the equivalent resistance is:

$$R_{\text{parallel}} = \frac{r}{n}$$

We're told that the resultant resistance when connected in parallel is $x$, so:

$$x = \frac{r}{n}$$

2. Resistances connected in series

When the same $n$ resistors, each of resistance $r$, are connected in series, the total or equivalent resistance $R_{\text{series}}$ is simply the sum of the individual resistances:

$$R_{\text{series}} = r + r + \cdots + r \quad \text{(n terms)}$$

So:

$$R_{\text{series}} = n \times r$$

3. Relating the two scenarios

From the parallel connection, we know that:

$$x = \frac{r}{n}$$

Thus, the resistance when the resistors are connected in series is:

$$R_{\text{series}} = n \times r = n \times \left( x \times n \right) = r \times n \times x$$

Therefore, the resistance when these $n$ resistors are connected in series is:

$$\boxed{r \times n \times x}$$