Rankers Physics
Topic: Laws of Motion
Subtopic: Linear Momentum and Second Law of Motion

A hammer of man 1 kg moving with a speed of 6 m/sec strikes a wall and comes to rest in 0.1 sec find average retarding force that stops the hammer :
40 N
50 N
60 N
None of these

Solution:

According to Newtons second law of motion, Force is time rate of change in momentum.

So, F = change in momentum / time

F= m (vf-vi)/t= 1 kg (0-6)/0.1= -60 N

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