Rankers Physics

Nucleus: Practice Problem & Solution

Energy released in the fission of a single $^{235}U$ nucleus is 200 MeV. The fission rate of a $^{235}U$ filled reactor operating at a power level of 5 W is (1993)
$1.56 \times 10^{-10} s^{-1}$
$1.56 \times 10^{11} s^{-1}$
$1.56 \times 10^{-16} s^{-1}$
$1.56 \times 10^{-17} s^{-1}$

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

Power $P = 5 W = 5 J/s$. Energy per fission $E = 200 MeV = 200 \times 10^6 \times 1.6 \times 10^{-19} J = 3.2 \times 10^{-11} J$. The fission rate is $n = P/E = 5 / (3.2 \times 10^{-11}) = 1.56 \times 10^{11} s^{-1}$.

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