Nucleus: Practice Problem & Solution
A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u = 931 MeV): (2013)
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:
Total energy liberated is $E = \Delta m \times 931 = 0.02866 \times 931 = 26.68$ MeV $\approx 26.7$ MeV. The mass of the resulting Helium nucleus is approximately 4 u. The energy liberated per atomic mass unit is $26.7 / 4 = 6.675$ MeV.
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