Rankers Physics
Topic: Current Electricity
Subtopic: Combination of Batteries

A carbon resistor is marked with the rings coloured brown, black green and gold. The resistance (in ohm) is :
\[3.2\times 10^{5}\] ±5%
\[1\times 10^{6}\] ±10%
\[1\times 10^{7}\] ±5%
\[1\times 10^{6}\] ±5%

Solution:

To determine the resistance of a carbon resistor with color bands brown, black, green, and gold, use the color code for resistors:


1. Color code values:

  • Brown: 11 (1st digit)
  • Black: 00 (2nd digit)
  • Green: 10510^5 (multiplier)
  • Gold: ±5%\pm 5\% (tolerance)

2. Calculate resistance:

The resistance is calculated as:

R=(1st digit×10+2nd digit)×multiplier.R = (\text{1st digit}\,\times\,10 + \text{2nd digit}) \,\times\, \text{multiplier}.

Substitute values:

R=(1×10+0)×105=10×105=106Ω.R = (1 \times 10 + 0) \times 10^5 = 10 \times 10^5 = 10^6 \, \Omega.

This is equal to:

R=1MΩ(megaohm).R = 1 \, \text{M}\Omega \, (\text{megaohm}).


3. Tolerance:

The gold band indicates a tolerance of ±5%\pm 5\%, so the resistance can vary between:

1MΩ±5%.1 \, \text{M}\Omega \pm 5\%.


Final Answer:

The resistance is:

1MΩ±5%.\boxed{1 \, \text{M}\Omega \, \pm 5\%.}

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