Rankers Physics

Nucleus: Practice Problem & Solution

Two radioactive substances A and B have decay constants $5\lambda$ and $\lambda$ respectively. At t = 0 they have the same number of nuclei. The ratio of number of nuclei of A to those of B will be $(1/e)^2$ after a time interval: (2007)
$4\lambda$
$2\lambda$
$1/2\lambda$
$1/4\lambda$

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

$N_A = N_0 e^{-5\lambda t}$ and $N_B = N_0 e^{-\lambda t}$. The ratio is $N_A/N_B = e^{-4\lambda t} = (1/e)^2 = e^{-2}$. This gives $4\lambda t = 2$, which implies $t = 1/2\lambda$.

Leave a Reply

Your email address will not be published. Required fields are marked *