Rankers Physics

Nucleus: Practice Problem & Solution

The binding energy per nucleon is maximum in case of (1993)
$ _2^4He $
$ _{26}^{56}Fe $
$ _{56}^{141}Ba $
$ _{92}^{235}U $

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

The binding energy per nucleon curve peaks around mass number A = 56. Thus, $ _{26}^{56}Fe $ has the maximum binding energy per nucleon, which is approximately 8.8 MeV.

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