Rankers Physics

Nucleus: Practice Problem & Solution

A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the Binding Energy in the process is: (2021)
9.4 MeV
804 MeV
216 MeV
0.9 MeV

Solution Explained:

To solve this problem, we apply the core principles of Nucleus. Understanding the underlying formula is key to arriving at the correct answer below:

Initial binding energy = $ 240 \times 7.6 $ MeV. Final binding energy of the two fragments = $ 2 \times (120 \times 8.5) = 240 \times 8.5 $ MeV. Total gain in binding energy = $ 240 \times (8.5 - 7.6) = 240 \times 0.9 = 216 $ MeV.

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