Rankers Physics

Photoelectric Effects and deBroglie Equation: Practice Problem & Solution

The energy of a photon of wavelength $\lambda$ is (1988)
$hc\lambda$
$\frac{hc}{\lambda}$
$\frac{hc}{\lambda^2}$
$\frac{\lambda}{hc}$

Solution Explained:

To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:

The energy of a photon in terms of wavelength is given by the relation $E = \frac{hc}{\lambda}$.

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