Photoelectric Effects and deBroglie Equation: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Photoelectric Effects and deBroglie Equation. Understanding the underlying formula is key to arriving at the correct answer below:

Energy of one photon is $E = h\nu = 6.63 \times 10^{-34} \times 880 \times 10^3 = 5.834 \times 10^{-28} J$. Number of photons emitted per second is $n = \frac{P}{E} = \frac{10 \times 10^3}{5.834 \times 10^{-28}} \approx 1.71 \times 10^{31}$.