Rankers Physics

Young's Double Slit Experiment: Practice Problem & Solution

The Young's double slit experiment is performed with blue and with green light of wavelengths $4360 \AA$ and $5460 \AA$ respectively. If x is the distance of 4th maxima from the central one, then: (1990)
$x(blue) = x(green)$
$x(blue) > x(green)$
$x(blue) < x(green)$
$\frac{x(blue)}{x(green)} = \frac{5460}{4360}$

Solution Explained:

To solve this problem, we apply the core principles of Young's Double Slit Experiment. Understanding the underlying formula is key to arriving at the correct answer below:

The distance of the nth maximum from the central maximum is $x = \frac{n\lambda D}{d}$. Thus, $x \propto \lambda$. Since $\lambda_{blue} < \lambda_{green}$, it follows that $x(blue) < x(green)$.

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