Rankers Physics

Young's Double Slit Experiment: Practice Problem & Solution

In Young's double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus is immersed in water of refractive index 4/3 without disturbing the geometrical arrangement, the new fringe width will be: (1990)
0.30 mm
0.40 mm
0.53 mm
450 microns

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Young's Double Slit Experiment. Understanding the underlying formula is key to arriving at the correct answer below:

Fringe width in a medium of refractive index $\mu$ is $\beta' = \frac{\beta}{\mu}$. Given $\beta = 0.4 mm$ and $\mu = 4/3$, the new fringe width is $\beta' = \frac{0.4}{4/3} = 0.30 mm$.

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