Rankers Physics

Young's Double Slit Experiment: Practice Problem & Solution

In a Young's double slit experiment, a student observes 8 fringes in a certain segment of screen when a monochromatic light of 600 nm wavelength is used. If the wavelength of light is changed to 400 nm, then the number of fringes he would observe in the same region of the screen is (2022)
12
6
8
9

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Young's Double Slit Experiment. Understanding the underlying formula is key to arriving at the correct answer below:

The width of the screen segment remains constant. Thus, $n_1 \beta_1 = n_2 \beta_2$, which implies $n_1 \lambda_1 = n_2 \lambda_2$. Substituting the values: $8 \times 600 = n_2 \times 400$, giving $n_2 = 12$ fringes.

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