Refraction by Plane Surfaces: Practice Problem & Solution
A bubble in glass slab ($\mu = 1.5$) when viewed from one side appears at $5 cm$ and $2 cm$ from other side, then thickness of slab is: (2000)
Solution Explained:
To solve this problem, we apply the core principles of Refraction by Plane Surfaces. Understanding the underlying formula is key to arriving at the correct answer below:
Total apparent thickness of the glass slab is $d_{app} = 5 + 2 = 7 cm$.
Using the relation $d_{app} = \frac{t}{\mu}$, the real thickness is $t = d_{app} \times \mu$.
Substituting the given values, $t = 7 \times 1.5 = 10.5 cm$.
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