Refraction by Plane Surfaces: Practice Problem & Solution
A light ray falls on a glass surface of refractive index $\sqrt{3}$, at an angle $60^\circ$. The angle between the refracted and reflected rays would be : (2022)
Solution Explained:
To solve this problem, we apply the core principles of Refraction by Plane Surfaces. Understanding the underlying formula is key to arriving at the correct answer below:
By Snell's law, $1 \times \sin(60^\circ) = \sqrt{3} \times \sin(r)$, which gives $\sin(r) = 1/2$, so angle of refraction $r = 30^\circ$.
By law of reflection, angle of reflection is equal to angle of incidence $i = 60^\circ$.
Angle between reflected and refracted rays is $180^\circ - (i + r) = 180^\circ - (60^\circ + 30^\circ) = 90^\circ$.
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