Solution:
The kinetic energy gained by the electron is equal to the work done by the electric field:
\[
eV = \frac{1}{2} m v^2
\]
Rearranging for \(v\):
\[
v = \sqrt{\frac{2eV}{m}}
\]
This shows that \(v \propto \sqrt{V}\).
If an electron is accelerated from rest through a potential difference V, then its final speed is proportional to :
Leave a Reply