8. A conducting circular loop is placed in a uniform magnetic field, $B = 0.025 T$ with its plane perpendicular to the loop. The radius of the loop is made to shrink at a constant rate of $1 mm s^{-1}$. The induced emf when the radius is $2 cm$ is: (2010 Pre)
Solution:
Flux is $\Phi = B \cdot A = B \cdot \pi r^2$. Magnitude of induced emf is $e = |\frac{d\Phi}{dt}| = B \cdot 2\pi r |\frac{dr}{dt}|$.
Given $B = 0.025 T$, $r = 2 cm = 0.02 m$, and $|\frac{dr}{dt}| = 1 mm s^{-1} = 10^{-3} m s^{-1}$.
$e = 0.025 \cdot 2\pi(0.02) \cdot (10^{-3}) = \pi \times 10^{-6} V = \pi \mu V$.
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