NEET Physics Question - Electrostatics

There exists a uniform electric field in the space as shown. Four points A, B, C and D are marked which are equidistant from the origin. If \(V_{A} , V_{B} , V_{C} and V_{D}\) are their potentials, respectively :

\[V_{B}\gt V_{B}\gt V_{C}\gt V_{D} \]

\[V_{A}\gt V_{B}\gt V_{D}\gt V_{C} \]

\[V_{A}= V_{B}\gt V_{C}= V_{D} \]

\[V_{B}\gt V_{C}\gt V_{A}\gt V_{D} \]

Solution:

In a uniform electric field, the electric potential decreases in the direction of the field. From the diagram:

1. Direction of the electric field: The field points downward and to the left (parallel to lines \(C \to D\)).

2. Potential relation:
- Points further along the direction of the field have lower potential.
- Points opposite to the field direction have higher potential.

3. Comparison of potentials:
- \(A\): Least aligned with the field direction (highest potential).
- \(B\): Slightly more aligned with the field direction than \(A\).
- \(D\): More aligned with the field direction than \(B\).
- \(C\): Most aligned with the field direction (lowest potential).

Thus, the potential order is:
\[
V_A > V_B > V_D > V_C
\]

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Solution:

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