Power of Electrical Circuit: Practice Problem & Solution
Two resistors of resistance, $100\text{ }\Omega$ and $200\text{ }\Omega$ are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in $100\text{ }\Omega$ to that in $200\text{ }\Omega$ in a given time is: (2022)
Solution Explained:
To solve this problem, we apply the core principles of Power of Electrical Circuit. Understanding the underlying formula is key to arriving at the correct answer below:
In a parallel combination, voltage across each resistor is the same. Thermal energy $H = \frac{V^2 t}{R}$, which means $H \propto \frac{1}{R}$. Thus, $H_1 / H_2 = R_2 / R_1 = 200 / 100 = 2 : 1$.
Leave a Reply