
Solution:
Number of Electric Field line is proportional to amount of charge. so,
\[ \frac{Q_{2}}{Q_{1}}=\frac{-6}{9}=\frac{-2}{3} \]
Number of Electric Field line is proportional to amount of charge. so,
\[ \frac{Q_{2}}{Q_{1}}=\frac{-6}{9}=\frac{-2}{3} \]
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