Combination of Batteries: Practice Problem & Solution
The internal resistance of a $2.1 \text{ V}$ cell which gives a current of $0.2 \text{ A}$ through a resistance of $10 \Omega$ is: (2013)
Solution Explained:
To solve this problem, we apply the core principles of Combination of Batteries. Understanding the underlying formula is key to arriving at the correct answer below:
Using the relation $I = \frac{E}{R + r}$, we substitute the given values: $0.2 = \frac{2.1}{10 + r}$. Solving for $r$, we get $10 + r = \frac{2.1}{0.2} = 10.5$, which yields $r = 0.5 \Omega$.
Leave a Reply