Solution:
For springs in series, the equivalent spring constant $k_{eq}$ is given by $\frac{1}{k_{eq}} = \frac{1}{k_1} + \frac{1}{k_2}$. Thus $k_{eq} = \frac{k_1 k_2}{k_1 + k_2}$.
Two springs of spring constants $k_1$ and $k_2$ are joined in series. The effective spring constant of the combination is given by: (2004)
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