Solution:
Total energy $E = \frac{1}{2}kA^2$. Halfway to the endpoint means $x = A/2$.\nPotential energy $U = \frac{1}{2}kx^2 = \frac{1}{2}k(A/2)^2 = \frac{1}{4}(\frac{1}{2}kA^2)$.\nTherefore, $U = E/4$.
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is: (2003)
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