The efficiency of a Carnot engine operating with reservoir temperature of $100\text{ }^\circ\text{C}$ and $-23\text{ }^\circ\text{C}$ will be: (1997)$\frac{373+250}{373}$$\frac{373-250}{373}$$\frac{100-23}{100}$$\frac{100+23}{100}$Solution:Efficiency $\eta = 1 - \frac{T_2}{T_1} = 1 - \frac{250\text{ K}}{373\text{ K}} = \frac{373-250}{373}$.
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