Uncategorized: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Using the adiabatic relation between pressure and temperature, $\frac{P_2}{P_1} = \left(\frac{T_2}{T_1}\right)^{\frac{\gamma}{\gamma-1}}$. Substituting $T_1 = 300\text{ K}$, $T_2 = 1200\text{ K}$, and $\gamma = 1.4$, we get $P_2 = 2 \times (4)^{3.5} = 256\text{ atm}$.