NEET Physics Question - Thermal Physics

Rankers Physics

Topic: Thermal Physics

Thermal capacity of $40 text{ g}$ of aluminum ($s = 0.2 text{ cal/g K}$) is: (1990)

$168 text{ J/K}$

$672 text{ J/K}$

$840 text{ J/K}$

$33.6 text{ J/K}$

Thermal capacity $= ms = 40 cdot 0.2 = 8 text{ cal/K} = 8 cdot 4.2 text{ J/K} = 33.6 text{ J/K}$