Moment of Inertia of Disc about Tangential Axis – Rankers Physics

Moment of Inertia of Disc about Tangential Axis

The moment of inertia of a uniform circular disc of radius $R$ and mass $M$ about an axis touching the disc at its diameter and normal to the disc is: (2006, 2005)

$\frac{1}{2}MR^2$

$MR^2$

$\frac{2}{5}MR^2$

$\frac{3}{2}MR^2$

Using the parallel axis theorem, $I = I_{cm} + Md^2$. Here $I_{cm} = \frac{1}{2}MR^2$ and $d = R$, so $I = \frac{1}{2}MR^2 + MR^2 = \frac{3}{2}MR^2$.