Power delivered to particle under uniform acceleration – Rankers Physics

Power: Practice Problem & Solution

A particle of mass $M$ starting from rest undergoes uniform acceleration. If the speed acquired in time $T$ is $V$, the power delivered to the particle is: (2010 Mains)
$\frac{1}{2} \frac{MV^2}{T^2}$
$\frac{2MV^2}{T}$
$\frac{MV^2}{T^2}$
$\frac{1}{2} \frac{MV^2}{T}$

Solution Explained:

To solve this problem, we apply the core principles of Power. Understanding the underlying formula is key to arriving at the correct answer below:

Power delivered is the rate of change of kinetic energy: $P = \frac{\Delta K}{T} = \frac{\frac{1}{2}MV^2 - 0}{T} = \frac{1}{2}\frac{MV^2}{T}$.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. If the kinetic energy of a body increases by 800%, its momentum increases by
2. The kinetic energy acquired by a mass \(m\) in travelling distance \(d\), starting from rest, under the action of a constant force is directly proportional to: (1994)
3. The only force acting on a \(2\text{ kg}\) body as it moves along the positive x axis has component \(F_x = -6x\text{ N}\), where x is in metre. The velocity of the body at \(x = 3\text{ m}\) is \(8\text{ m/s}\). The velocity of the body at \(x = 4\text{ m}\) is:
4. Water falls from a height of \(60\text{ m}\) at the rate of \(15\text{ kg/s}\) to operate a turbine. The losses due to frictional force are \(10%\) of the input energy. How much power is generated by the turbine? (\(g = 10\text{ m/s}^2\))
5. Two springs \(A\) and \(B\) (\(K_A = 2K_B\)) are stretched by same suspended weights then ratio of work done in stretching is (1999)