Friction: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Friction. Understanding the underlying formula is key to arriving at the correct answer below:

For equilibrium, the weight of the hanging part must equal the maximum static friction on the table. If (x) is the fraction hanging, then \(xMg = mu(1-x)Mg\). So, \(x = \mu(1-x)\). This gives \(x = \frac{\mu}{1+\mu}\). With \(\mu = 0.25\), \(x = \frac{0.25}{1+0.25} = \frac{0.25}{1.25} = 0.20\) or (20%).