Friction: Practice Problem & Solution
On the horizontal surface of a truck a block of mass \(1\text{ kg}\) is placed \((\mu = 0.6)\) and truck is moving with acceleration \(5\text{ m/s}^2\) then the frictional force on block will be: (2001)
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Friction. Understanding the underlying formula is key to arriving at the correct answer below:
Required force for block to accelerate with truck is \(F = ma_{truck}\). Maximum static friction is \(f_{s,max} = \mu mg\). If \(F \leq f_{s,max}\), friction equals (F). Here, \(F = 1 \times 5 = 5\text{ N}\) and \(f_{s,max} = 0.6 \times 1 \times 10 = 6\text{ N}\). Since \(5 \leq 6\), the frictional force is \(5\text{ N}\).
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