Frictional force on a block in an accelerating truck – Rankers Physics

Friction: Practice Problem & Solution

On the horizontal surface of a truck a block of mass \(1\text{ kg}\) is placed \((\mu = 0.6)\) and truck is moving with acceleration \(5\text{ m/s}^2\) then the frictional force on block will be: (2001)
5 N
6 N
5.88 N
8 N

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Friction. Understanding the underlying formula is key to arriving at the correct answer below:

Required force for block to accelerate with truck is \(F = ma_{truck}\). Maximum static friction is \(f_{s,max} = \mu mg\). If \(F \leq f_{s,max}\), friction equals (F). Here, \(F = 1 \times 5 = 5\text{ N}\) and \(f_{s,max} = 0.6 \times 1 \times 10 = 6\text{ N}\). Since \(5 \leq 6\), the frictional force is \(5\text{ N}\).

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