Acceleration of a block on a rough horizontal surface – Rankers Physics

Friction: Practice Problem & Solution

A block of mass \(10\text{ kg}\) placed on rough horizontal surface having coefficient of friction \(\mu = 0.5\), if a horizontal force of \(100text{ N}\) acting on it then acceleration of the block will be: (2002)
\(10\text{ m/s}^2\)
\(5\text{ m/s}^2\)
\(15\text{ m/s}^2\)
\(0.5\text{ m/s}^2\)

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Friction. Understanding the underlying formula is key to arriving at the correct answer below:

Calculate max friction \(f = \mu mg\). Compare with applied force (F). If (F > f), then (a = (F-f)/m). Here, (f = 0.5 \times 10 \times 10 = 50\text{ N}). So, (a = (100-50)/10 = 5\text{ m/s}^2).

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