Uncategorized: Practice Problem & Solution
A stone is dropped from a height \( h \). It hits the ground with a certain momentum \( P \). If the same stone is dropped from a height \( 100\% \) more than the previous height, the momentum when it hits the ground will change by: (2012 Mains)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
Momentum \( P = msqrt{2gh} \). If height increases by \( 100\% \), new height \( h' = 2h \). New momentum \( P' = msqrt{2g(2h)} = sqrt{2}P \). Percentage change \( \frac{P' - P}{P} \times 100\% = (sqrt{2} - 1)\times 100\% \approx 41.4\% \).
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