Uncategorized: Practice Problem & Solution
A block has been placed on an inclined plane with the slope angle \(theta\), block slides down the plane at constant speed. The coefficient of kinetic friction is equal to: (1993)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
When a block slides down an inclined plane at constant speed, the net force along the plane is zero. The component of gravitational force along the plane is \(mg sin \theta\). The kinetic friction force is \(mu_k mg cos \theta\). Equating these, we get \(mu_k = \tan \theta\).
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