Acceleration of Fan Blade Tip – Rankers Physics

Uncategorized: Practice Problem & Solution

An electric fan has blades of length \( 30 text{ cm} \) measured from the axis of rotation. If the fan is rotating at \( 120 text{ rpm} \), the acceleration of a point on the tip of the blade is: (1990)
\( 1600 text{ m s}^{-2} \)
\( 47.4 text{ m s}^{-2} \)
\( 23.7 text{ m s}^{-2} \)
\( 50.55 text{ m s}^{-2} \)

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Given: Radius \( r = 30 text{ cm} = 0.30 text{ m} \). Frequency \( f = 120 text{ rpm} = frac{120}{60} = 2 text{ rps} \). Angular velocity \( omega = 2pi f = 2pi (2) = 4pi text{ rad/s} \). The centripetal acceleration is \( a_c = romega^2 \). Thus, \( a_c = 0.30 times (4pi)^2 = 0.30 times 16pi^2 approx 0.30 times 16 times (3.14159)^2 approx 47.37 text{ m s}^{-2} \). Approximately \( 47.4 text{ m s}^{-2} \).

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