Change in Velocity During Turn – Rankers Physics

Uncategorized: Practice Problem & Solution

A bus is moving on a straight road towards north with a uniform speed of \(50 text{ km/hour}text{ then it turns left through 90°. If the speed remains unchanged after turning, the increase in the velocity of bus in the turning process is: (1989)}\
\(70.7 text{ km/hr along south-west direction}\)
Zero
\(50 text{ km/hr along west}\)
\(70.7 text{ km/hr along north-west direction}\)

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Concept: Change in velocity is a vector difference.
Formula: \(Delta vec{v} = vec{v}_f - vec{v}_i\).
Initial velocity \(vec{v}_i = 50hat{j}\). Final velocity \(vec{v}_f = -50hat{i}\).
\(Delta vec{v} = -50hat{i} - 50hat{j}\). Magnitude \(|Delta vec{v}| = sqrt{(-50)^2 + (-50)^2} = 50sqrt{2} approx 70.7text{ km/hr}\).
Direction: South-West.

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