Solution:
The speed of sound in a resonance tube is given by \(v = 2 f (l_2 - l_1)\). Substituting \(f = 340\text{ Hz}\), \(l_1 = 0.25\text{ m}\), and \(l_2 = 0.80\text{ m}\), we get \(v = 2(340)(0.80 - 0.25) = 374\text{ m/s}\).
In a resonance tube at room temperature two successive resonance lengths of air column are \(25\text{ cm}\) and \(80\text{ cm}\). If the frequency of tuning fork is \(340\text{ Hz}\) then the speed of sound at that temperature is
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