Current in Series LCR Circuit – Rankers Physics
Topic: Alternating Current
Subtopic: LR, RC and LCR Circuits

Current in Series LCR Circuit

Consider a series \(LCR\) circuit in which reactance and resistance are \(100\ \Omega\) each. When the circuit is connected to ac source \(220\text{ V}\), \(50\text{ Hz}\), then current drawn from the source is
\(2.2\sqrt{2}\text{ A}\)
\(1.1\sqrt{2}\text{ A}\)
\(3.3\sqrt{2}\text{ A}\)
\(2.2\text{ A}\)

Solution:

Here, \(R = 100\ \Omega\) and net reactance \(X = 100\ \Omega\). Total impedance is \(Z = \sqrt{R^2 + X^2} = 100\sqrt{2}\ \Omega\). The current \(I = \frac{V}{Z} = \frac{220}{100\sqrt{2}} = 1.1\sqrt{2}\text{ A}\).

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