Solution:
To convert a galvanometer into a voltmeter, a high resistance \(R\) is connected in series: \(V = I_g(G + R) \implies 10 = 10^{-3}(12 + R) \implies R = 9988\ \Omega\).
To convert a galvanometer into a voltmeter, a high resistance \(R\) is connected in series: \(V = I_g(G + R) \implies 10 = 10^{-3}(12 + R) \implies R = 9988\ \Omega\).
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