Standing Wave in String and Organ Pipe: Practice Problem & Solution

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Standing Wave in String and Organ Pipe. Understanding the underlying formula is key to arriving at the correct answer below:

Frequency \(f \propto \frac{1}{L}\), so \(\frac {f_1}{f_2} = \frac{26}{25}\). Since \(\f_1 -\f_2 = 10\), we have \(26x - 25x = 10 \Rightarrow x = 10\). Thus \(f_1 = 260\text{ Hz}\) and \(f_2 = 250\text{ Hz}\).