Rankers Physics
Topic: Thermal Physics
Subtopic: Heat Transfer - Conduction and Convection

A body of length 1 m having cross-sectional area 0.75 m2 has heat flow through it at the rate of 6000 J/s. The difference between two ends of conductor if K = 200 J m–¹K–¹ is
20°C
40°C
80°C
100°C

Solution:

To find the temperature difference (ΔT) between the two ends of the conductor, we can use the formula for heat conduction:

\[
Q = \frac{K \cdot A \cdot \Delta T}{L}
\]

Where:
- \( Q = 6000 \, \text{J/s} \)
- \( K = 200 \, \text{J} \, \text{m}^{-1} \, \text{K}^{-1} \)
- \( A = 0.75 \, \text{m}^2 \)
- \( L = 1 \, \text{m} \)

Rearranging to solve for ΔT:

\[
\Delta T = \frac{Q \cdot L}{K \cdot A}
\]

\[
\Delta T = \frac{6000 \cdot 1}{200 \cdot 0.75} = 40 \, \text{K}
\]

The temperature difference between the two ends is 40 K or 40 °C

Leave a Reply

Your email address will not be published. Required fields are marked *