Solution:
The magnetic force per unit length between two parallel current-carrying wires is given by \(F/L = \frac{\mu_0 i_1 i_2}{2\pi d}\). Since \(i_1 = i_2 = i\), \(F/L = \frac{\mu_0 i^2}{2\pi d}\), which is directly proportional to \(i^2\).
Two long thin parallel wires separated by a distance \(d\) are carrying a current \(i\) each. The magnitude of the force per unit length applied by one wire on the other is
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