Solution:
From \(\omega_1 = 1020\pi\) and \(\omega_2 = 1004\pi\), we get $ f_1 = 510\text{ Hz} $ and \( f_2 = 502\text{ Hz}\). The beat frequency is \(|f_1 - f_2| = 8\text{ Hz}\).
If two sound waves represented by \(y_1 = 10 \sin(1020\pi t - K_1x)\) and \(y_2 = 10 \sin(1004\pi t - K_2x)\) are superposed at \(x = 0\), then beat frequency is
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