Equation of state for nitrogen gas – Rankers Physics

Thermodynamics: Practice Problem & Solution

The equation of state for \(14\text{ g}\) nitrogen gas at a pressure \(P\) and temperature \(T\), when occupying a volume \(V\) will be
\(PV = 14RT\)
\(PV = \frac{1}{2}RT\)
\(PV = RT\)
\(PV = 2RT\)

Solution Explained:

To solve this problem, we apply the core principles of Thermodynamics. Understanding the underlying formula is key to arriving at the correct answer below:

The molecular mass of nitrogen gas \((\text{N}_2)\) is \(28\text{ g/mol}\). The number of moles is \(n = \frac{14}{28} = 0.5\). Thus, using \(PV = nRT\), we get \(PV = \frac{1}{2}RT\).

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