Solution:
The maximum efficiency is given by the Carnot efficiency formula: \(\eta = 1 - \frac{T_2}{T_1}\). Here, \(T_1 = 600\text{ K}\) and \(T_2 = 200\text{ K}\), so \(\eta = 1 -\frac{200}{600} = 1 - \frac{1}{3} = \frac{2}{3} \approx 66.67%\).
In ideal condition, the maximum efficiency that can be derived from a heat engine built operating between \(600\text{ K}\) reservoir and \(200\text{ K}\) sink, is
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