Solution:
Intensity of magnetisation \(I = \frac{M}{V}\). Volume \(V = 0.10 \times 0.05 \times 0.04 = 2 \times 10^{-4} \text{m}^3\). So, \(I = \frac{2.5}{2 \times 10^{-4}} = 1.25 \times 10^4 \text{A/m}\).
Intensity of magnetisation \(I = \frac{M}{V}\). Volume \(V = 0.10 \times 0.05 \times 0.04 = 2 \times 10^{-4} \text{m}^3\). So, \(I = \frac{2.5}{2 \times 10^{-4}} = 1.25 \times 10^4 \text{A/m}\).
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