Solution:
To get a real image of the same size, the image distance from the lens must be \(v = 2f\). Here, \(v = x\), therefore \(x = 2f ⇒ f = \frac{x}{2}\).
An object is mounted on a wall. Its image of equal size is to be obtained on a parallel wall with the help of a convex lens placed between these walls. The lens is kept at distance \(x\) in front of the second wall. The required focal length of the lens will be
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