Solution:

For equal distances, average speed \(v_{avg} = \frac{2v_1 v_2}{v_1 + v_2}\). Given \(v_1 = 40 \text{ km/h}\) and \(v_2 = 60 \text{ km/h}\). So, \(v_{avg} = \frac{2 \times 40 \times 60}{40 + 60} = \frac{4800}{100} = 48 \text{ km/h}\).